3[(5x+1)-4]=4(2x+3)

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Solution for 3[(5x+1)-4]=4(2x+3) equation:


Simplifying
3[(5x + 1) + -4] = 4(2x + 3)

Reorder the terms:
3[(1 + 5x) + -4] = 4(2x + 3)

Remove parenthesis around (1 + 5x)
3[1 + 5x + -4] = 4(2x + 3)

Reorder the terms:
3[1 + -4 + 5x] = 4(2x + 3)

Combine like terms: 1 + -4 = -3
3[-3 + 5x] = 4(2x + 3)
[-3 * 3 + 5x * 3] = 4(2x + 3)
[-9 + 15x] = 4(2x + 3)

Reorder the terms:
-9 + 15x = 4(3 + 2x)
-9 + 15x = (3 * 4 + 2x * 4)
-9 + 15x = (12 + 8x)

Solving
-9 + 15x = 12 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
-9 + 15x + -8x = 12 + 8x + -8x

Combine like terms: 15x + -8x = 7x
-9 + 7x = 12 + 8x + -8x

Combine like terms: 8x + -8x = 0
-9 + 7x = 12 + 0
-9 + 7x = 12

Add '9' to each side of the equation.
-9 + 9 + 7x = 12 + 9

Combine like terms: -9 + 9 = 0
0 + 7x = 12 + 9
7x = 12 + 9

Combine like terms: 12 + 9 = 21
7x = 21

Divide each side by '7'.
x = 3

Simplifying
x = 3

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